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10x^2-111x+168=0
a = 10; b = -111; c = +168;
Δ = b2-4ac
Δ = -1112-4·10·168
Δ = 5601
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-111)-\sqrt{5601}}{2*10}=\frac{111-\sqrt{5601}}{20} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-111)+\sqrt{5601}}{2*10}=\frac{111+\sqrt{5601}}{20} $
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